(x^2+3x-4)-(x-5)=

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Solution for (x^2+3x-4)-(x-5)= equation:


Simplifying
(x2 + 3x + -4) + -1(x + -5) = 0

Reorder the terms:
(-4 + 3x + x2) + -1(x + -5) = 0

Remove parenthesis around (-4 + 3x + x2)
-4 + 3x + x2 + -1(x + -5) = 0

Reorder the terms:
-4 + 3x + x2 + -1(-5 + x) = 0
-4 + 3x + x2 + (-5 * -1 + x * -1) = 0
-4 + 3x + x2 + (5 + -1x) = 0

Reorder the terms:
-4 + 5 + 3x + -1x + x2 = 0

Combine like terms: -4 + 5 = 1
1 + 3x + -1x + x2 = 0

Combine like terms: 3x + -1x = 2x
1 + 2x + x2 = 0

Solving
1 + 2x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + x)(1 + x) = 0

Subproblem 1

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-1, -1}

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